Classification of elements and Periodic Table

Unit 4 · General and Physical Chemistry · 5 teaching hours · 25 min read

Classification of elements and Periodic Table

What the syllabus asks for 4
  • Modern periodic law and modern periodic table; classification into groups, periods and blocks
  • IUPAC classification of elements
  • Nuclear charge and effective nuclear charge
  • Periodic trend and periodicity: atomic radii, ionic radii, ionization energy, electron affinity, electronegativity, metallic character

There are 118 known elements. Learning each one separately would be hopeless; learning the pattern they fall into takes an afternoon.

Arrange the elements in order of atomic number and their properties come back again and again at regular intervals.

This unit explains why the table has the shape it has, and how six properties — atomic radius, ionic radius, ionization energy, electron affinity, electronegativity and metallic character — change in a way you can predict.

What the examiner wants

Nearly every NEB question on this unit is one of three kinds: (i) place an element given its electronic configuration, (ii) compare two elements on a trend, (iii) explain an irregularity (Be above B, N above O, Cl above F).

Stating the trend earns half the marks. The reason — always effective nuclear charge, shell number or half-filled stability — earns the other half.

4.1 Modern periodic law and modern periodic table

Mendeleev (1869) arranged the elements by increasing atomic mass, but had to reverse some pairs to keep the chemistry right: Ar (39.9) before K (39.1), Co before Ni, Te before I. In 1913 Henry Moseley measured the frequency \nu of the characteristic X-rays emitted by different metals and found

\sqrt{\nu} = a(Z - b)

where Z is the atomic number and a, b are constants. Atomic number, not atomic mass, is the fundamental property of an element, and every reversal disappears when the elements are ordered by Z.

Modern periodic law

The physical and chemical properties of the elements are periodic functions of their atomic numbers.

The long form (modern) periodic table has 7 horizontal periods and 18 vertical groups. A period number equals the principal quantum number n of the outermost shell being filled, so the number of elements in a period is fixed by how many orbitals that shell offers.

Period n Subshells filled No. of elements Name
1 1 1s 2 very short
2 2 2s 2p 8 short
3 3 3s 3p 8 short
4 4 4s 3d 4p 18 long
5 5 5s 4d 5p 18 long
6 6 6s 4f 5d 6p 32 very long
7 7 7s 5f 6d 7p 32 very long

Elements in the same group have the same valence configuration, so they behave alike: all of group 1 reacts with water to give a hydroxide and hydrogen, all of group 17 forms an X⁻ ion.

Depending on which subshell receives the last electron, an element belongs to one of four blocks.

Block Last electron enters Outer configuration Groups Character
s ns ns¹⁻² 1, 2 (and He) soft, very reactive metals
p np ns² np¹⁻⁶ 13–18 metals, metalloids, non-metals
d (n−1)d (n−1)d¹⁻¹⁰ ns⁰⁻² 3–12 transition metals
f (n−2)f (n−2)f¹⁻¹⁴ (n−1)d⁰⁻¹ ns² inside group 3 inner transition

figure
Figure 1. Block structure of the long-form periodic table. Period number = n of the outermost shell; the block is fixed by the subshell that receives the last electron.

4.2 IUPAC classification of elements

The old labels IA, IIA … IB, IIB were used differently in Europe and America, which caused confusion. In 1988 IUPAC replaced them: the groups are simply numbered 1 to 18 from left to right.

IUPAC group Old (CAS) Family name Valence configuration
1 IA Alkali metals ns¹
2 IIA Alkaline earth metals ns²
3–12 IIIB–IIB Transition elements (n−1)d¹⁻¹⁰ns¹⁻²
13 IIIA Boron family ns²np¹
14 IVA Carbon family ns²np²
15 VA Nitrogen family ns²np³
16 VIA Chalcogens ns²np⁴
17 VIIA Halogens ns²np⁵
18 0 Noble gases ns²np⁶ (He: 1s²)

IUPAC also fixed the quarrel over who discovered the very heavy elements by giving a systematic name to every element with Z > 100.

Write the digits of the atomic number, replace each digit by its Latin/Greek root, join them in order, and add -ium. The symbol is the first letter of each root.

The numerical roots
0 1 2 3 4 5 6 7 8 9
nil un bi tri quad pent hex sept oct enn
n u b t q p h s o e

Two spelling rules: bi + ium → bium and tri + ium → trium (one i is dropped), and enn + nil → ennil (one n is dropped).

Worked example 4.1 — systematic names

Problem. Give the IUPAC systematic name and symbol for the elements with Z = 105, Z = 109 and Z = 113.

Solution.

Z = 105 \Rightarrow 1, 0, 5 → un + nil + pent + ium = Unnilpentium, symbol Unp.

Z = 109 \Rightarrow 1, 0, 9 → un + nil + enn + ium = Unnilennium, symbol Une.

Z = 113 \Rightarrow 1, 1, 3 → un + un + tri + ium; triium loses one i, giving Ununtrium, symbol Uut.

(These three are now officially dubnium Db, meitnerium Mt and nihonium Nh, but the systematic name is what NEB asks you to construct.)

4.3 Nuclear charge and effective nuclear charge

The nucleus carries a charge of +Ze. An outer electron, however, does not feel the full pull of +Ze, because the electrons between it and the nucleus push it outwards.

This partial cancellation is the screening or shielding effect, measured by the screening constant \sigma. What the electron actually feels is the effective nuclear charge:

Z_{\text{eff}} = Z - \sigma

Screening power depends on how close to the nucleus an orbital keeps its electron. Penetration falls in the order s > p > d > f, so the shielding power of the subshells also falls in the order s > p > d > f.

Effective nuclear charge

The effective nuclear charge is the net positive charge actually experienced by a particular electron in a multi-electron atom, after the shielding due to all the other electrons has been subtracted from the true nuclear charge.

\sigma can be estimated with Slater's rules. Write the configuration in the groups (1s)(2s,2p)(3s,3p)(3d)(4s,4p)… and, for an electron in an ns or np orbital, add up:

Other electrons located in Contribution to \sigma each
a group to the right (higher shells) 0.00
the same (ns, np) group 0.35 (but 0.30 in 1s)
the shell just inside, n-1 0.85
shell n-2 and deeper 1.00
Worked example 4.2 — effective nuclear charge

Problem. Calculate Z_{\text{eff}} felt by a 3s electron of sodium (Z = 11) and by a 3p electron of chlorine (Z = 17).

Solution. Sodium: (1s²)(2s²2p⁶)(3s¹). The 3s electron has no partner in its own group, eight electrons in the n-1 shell and two in the n-2 shell.

\sigma = (0 \times 0.35) + (8 \times 0.85) + (2 \times 1.00) = 0 + 6.80 + 2.00 = 8.80

Z_{\text{eff}} = 11 - 8.80 = 2.20

Chlorine: (1s²)(2s²2p⁶)(3s²3p⁵). The chosen 3p electron has six partners in the (3s,3p) group, eight electrons in shell 2 and two in shell 1.

\sigma = (6 \times 0.35) + (8 \times 0.85) + (2 \times 1.00) = 2.10 + 6.80 + 2.00 = 10.90

Z_{\text{eff}} = 17 - 10.90 = 6.10

Across period 3 the nuclear charge rises by 6 but the screening rises by only 2.10, so Z_{\text{eff}} almost triples. That single number explains every trend in the rest of this chapter.

Period 3 element Na Mg Al Si P S Cl
Z 11 12 13 14 15 16 17
Z_{\text{eff}} (Slater) 2.20 2.85 3.50 4.15 4.80 5.45 6.10
Atomic radius / pm 186 160 143 117 110 104 99
IE₁ / kJ mol⁻¹ 496 738 578 786 1012 1000 1251
Nuclear charge is not effective nuclear charge

Potassium (Z = 19) has a far bigger nuclear charge than lithium (Z = 3), yet its valence electron is held much more weakly.

The reason is that Z_{\text{eff}} for the outermost electron of every alkali metal is only about 2.2, while the electron sits in a shell of larger and larger n. Always compare Z_{\text{eff}} and n together, never Z alone.

4.4 Periodic trend and periodicity: atomic radii, ionic radii, ionization energy, electron affinity, electronegativity, metallic character

Periodicity is the repetition of similar properties after regular intervals in the periodic table. It happens because the outer-shell configuration repeats: every element in group 1 ends in ns¹, so every element in group 1 behaves alike.

Atomic radii

An atom has no sharp boundary, so radius is always defined operationally.

Type Defined as Used for
Covalent radius half the internuclear distance in X–X of a single bond non-metals, e.g. Cl 99 pm
Metallic radius half the internuclear distance of nearest atoms in the metal crystal metals, e.g. Na 186 pm
van der Waals radius half the distance of closest approach of two non-bonded atoms noble gases, e.g. Ar 154 pm

For the same element van der Waals radius > metallic radius > covalent radius.

Across a period the radius decreases: n stays the same while Z_{\text{eff}} rises, pulling the shell in. Down a group it increases: a whole new shell is added, which easily beats the rise in Z_{\text{eff}}.

figure
Figure 2. Atomic radii from real data. Left: the sharp contraction across periods 2 and 3. Right: the steady expansion down group 1 and group 17.

Ionic radii

A cation is always smaller than its parent atom: Na (186 pm) → Na⁺ (95 pm), because the whole 3s shell is removed and the remaining 10 electrons are pulled in by 11 protons.

An anion is always larger: Cl (99 pm) → Cl⁻ (181 pm), because the added electron increases electron–electron repulsion while Z is unchanged.

For an isoelectronic series — ions with the same number of electrons — size falls as nuclear charge rises:

Ion N³⁻ O²⁻ F⁻ Ne Na⁺ Mg²⁺ Al³⁺
Electrons 10 10 10 10 10 10 10
Protons 7 8 9 10 11 12 13
Radius / pm 171 140 136 — 95 65 50
Worked example 4.3 — ordering ions by size

Problem. Arrange O²⁻, F⁻, Na⁺, Mg²⁺ in increasing order of ionic radius and justify your answer.

Solution. Each ion has 10 electrons, so the screening is identical. Only the nuclear charge differs: Mg²⁺ (12 p) > Na⁺ (11 p) > F⁻ (9 p) > O²⁻ (8 p).

The charge per electron is 12/10 = 1.20, 1.10, 0.90 and 0.80 respectively, so the pull on each electron weakens in that order and the ions swell:

Mg²⁺ (65) < Na⁺ (95) < F⁻ (136) < O²⁻ (171) pm.

Ionization energy

Ionization energy

The first ionization energy (IE₁) is the minimum energy required to remove the most loosely bound electron from one mole of isolated gaseous atoms in their ground state: M(g) + IE₁ → M⁺(g) + e⁻. It is measured in kJ mol⁻¹ or eV atom⁻¹ (1 eV atom⁻¹ = 96.5 kJ mol⁻¹).

Successive values always increase, IE₁ < IE₂ < IE₃ …, because each electron is pulled from an ion of higher positive charge.

A very big jump marks the point at which a noble-gas core is broken: for sodium IE₁ = 496 but IE₂ = 4562 kJ mol⁻¹, which is why sodium forms Na⁺ and never Na²⁺.

Ionization energy increases across a period (Z_{\text{eff}} up, size down) and decreases down a group (size up, shielding up).

figure
Figure 3. First ionization energy against atomic number for the first 20 elements. Noble gases are maxima, alkali metals minima; the dips at B, O, Al and S are the half-filled and fully-filled anomalies.

Two irregularities are asked almost every year:

  • Be (899) > B (801). Beryllium's electron leaves a filled 2s² orbital, while boron's leaves a 2p orbital that is higher in energy and well shielded by 2s².
  • N (1402) > O (1314). Nitrogen is 2p³, a half-filled subshell with extra exchange stability and no paired electron. Oxygen is 2p⁴; the two electrons paired in one 2p orbital repel each other, so one is easier to pull off.

The same pair of reasons gives Mg > Al and P > S in period 3.

Electron affinity

Electron affinity

Electron affinity is the energy released when an electron is added to one mole of isolated gaseous atoms in the ground state: X(g) + e⁻ → X⁻(g) + energy.

A large positive electron affinity means a strong pull for the extra electron (the corresponding enthalpy change ΔH is negative).

Second electron affinity is always endothermic, because the electron must be forced onto an already negative ion: O⁻(g) + e⁻ → O²⁻(g) needs about +780 kJ mol⁻¹.

Electron affinity rises across a period and falls down a group, but the first member of each group breaks the rule.

figure
Figure 4. Left: electronegativity across period 3 and down group 17. Right: electron affinity, showing that Cl beats F and S beats O because the 2p subshell is too compact.

Fluorine (328) has a smaller electron affinity than chlorine (349), and oxygen (141) a smaller one than sulphur (200): in F and O the 2p subshell is so compact that the electrons already there repel the incoming one strongly.

Groups 2, 15 and 18 have near-zero or negative values because their subshells are filled or half-filled.

Electronegativity

Electronegativity

Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons towards itself. It is a relative, dimensionless number; on Pauling's scale fluorine, the most electronegative element, is 4.0 and caesium is 0.7.

It increases across a period and decreases down a group.

It is not the same as electron affinity: electron affinity belongs to an isolated atom and is an energy in kJ mol⁻¹, whereas electronegativity belongs to a bonded atom and has no units.

The electronegativity difference decides whether a bond is non-polar covalent, polar covalent or ionic (Unit 5).

Metallic character

Metallic (electropositive) character is the tendency to lose electrons. It runs opposite to ionization energy: it decreases across a period and increases down a group. The diagonal staircase B, Si, Ge, As, Sb, Te (the metalloids) marks the metal / non-metal boundary.

Property Across a period (left → right) Down a group Main reason
Atomic radius decreases increases Z_{\text{eff}} vs new shell
Ionic radius decreases (same charge) increases same
Ionization energy increases decreases Z_{\text{eff}} vs size and shielding
Electron affinity increases decreases Z_{\text{eff}} vs size
Electronegativity increases decreases Z_{\text{eff}} vs size
Metallic character decreases increases opposite of IE
Valency w.r.t. oxygen 1 → 7 constant valence electrons

photograph
(a) Alkali metal salts colour a flame: lithium red, sodium yellow, potassium lilac
diagram
(b) First ionisation energy against atomic number
Plate 4.P. Ionisation energy is the energy needed to remove the outermost electron from a gaseous atom, and it shows the periodicity of the table. (a) Alkali metal salts in a flame: the outer electron is easily excited and removed. (b) The graph of the first ionisation energies of elements 1 to 20 climbs across each period to a noble gas, helium at 24.59 eV, and then drops sharply to the next alkali metal. Down group 1, lithium 5.39 eV, sodium 5.14 eV and potassium 4.34 eV, the outer electron is farther from the nucleus and better shielded, so it is lost more easily and the metals grow more reactive.Photo credits: (a) Hegelrast, CC BY-SA 4.0.

Chapter summary

  • Modern periodic law: properties are periodic functions of atomic number, established by Moseley's relation \sqrt{\nu} = a(Z-b).
  • The long form has 7 periods (2, 8, 8, 18, 18, 32, 32 elements) and 18 IUPAC groups; blocks s, p, d, f are named after the subshell filled last.
  • Elements with Z > 100 are named systematically from the roots nil, un, bi, tri, quad, pent, hex, sept, oct, enn plus -ium.
  • Z_{\text{eff}} = Z - \sigma; screening power falls as s > p > d > f. Slater's rules give Z_{\text{eff}} = 2.20 for Na(3s) and 6.10 for Cl(3p).
  • Across a period: radius ↓, IE ↑, EA ↑, EN ↑, metallic character ↓. Down a group: radius ↑, IE ↓, EA ↓, EN ↓, metallic character ↑.
  • Cations are smaller and anions larger than the parent atom; in an isoelectronic series radius falls as the number of protons rises.
  • Anomalies: Be > B and N > O (and Mg > Al, P > S) in ionization energy because of filled 2s and half-filled 2p stability; Cl > F and S > O in electron affinity because the second-period atoms are too compact.

Practice questions

Group A — Multiple choice (1 mark each)

  1. An element has the configuration [Ar] 3d¹⁰ 4s² 4p³. It belongs to [1]agroup 13, p-blockbgroup 15, p-blockcgroup 5, d-blockdgroup 15, d-block
  2. The correct order of ionic radii is [1]aAl³⁺ > Mg²⁺ > Na⁺ > F⁻bO²⁻ > F⁻ > Na⁺ > Mg²⁺cNa⁺ > F⁻ > O²⁻ > N³⁻dF⁻ > O²⁻ > N³⁻ > Na⁺
  3. The first ionization energy of nitrogen is greater than that of oxygen because [1]anitrogen has higher nuclear chargebnitrogen has a half-filled 2p subshellcoxygen is more electronegativedoxygen has a larger radius
  4. The IUPAC systematic name of the element with Z = 106 is [1]aUnnilhexiumbUnnilsextiumcUnunhexiumdUnhexium
  5. Using Slater's rules, the effective nuclear charge felt by the 3s electron of sodium is [1]a11.00b8.80c2.20d1.00
Answers to Group A

1. (b) — the last electron enters 4p, so p-block; 2 + 3 = 5 valence electrons gives group 15 (arsenic, Z = 33).

2. (b) — all are isoelectronic with 10 electrons, so radius falls as protons rise: 8 < 9 < 11 < 12.

3. (b) — 2p³ is half-filled and has no paired 2p electron, so it is extra stable.

4. (a) — 1, 0, 6 → un + nil + hex + ium.

5. (c) — \sigma = 8(0.85) + 2(1.00) = 8.80, so Z_{\text{eff}} = 11 - 8.80 = 2.20.

Group B — Short answer (5 marks each)

  1. State the modern periodic law. Explain, in terms of orbital filling, why the second period contains 8 elements while the fourth contains 18. [5]
  2. Define effective nuclear charge. Using Slater's rules calculate Z_{\text{eff}} for a 3p electron of phosphorus (Z=15) and of sulphur (Z=16), and comment on the result. [5]
  3. Define ionization energy. Why is the second ionization energy of sodium (4562 kJ mol⁻¹) nearly nine times the first (496 kJ mol⁻¹)? [5]
  4. Why is the electron affinity of fluorine smaller than that of chlorine even though fluorine is the more electronegative element? Distinguish clearly between electron affinity and electronegativity. [5]
  5. Arrange with reasons: (i) Li, Be, B, C in increasing atomic radius; (ii) N³⁻, O²⁻, F⁻, Na⁺ in decreasing ionic radius. [5]
Answers to Group B

1. Properties are periodic functions of atomic number. Period 2 fills 2s and 2p only: 1 + 3 = 4 orbitals × 2 electrons = 8 elements. Period 4 fills 4s, then 3d, then 4p: 1 + 5 + 3 = 9 orbitals × 2 = 18 elements.

2. Z_{\text{eff}} = Z - \sigma. Phosphorus (1s²)(2s²2p⁶)(3s²3p³): \sigma = 4(0.35)+8(0.85)+2(1.00) = 1.40+6.80+2.00 = 10.20, so Z_{\text{eff}} = 15-10.20 = 4.80.

Sulphur (3s²3p⁴): \sigma = 5(0.35)+6.80+2.00 = 10.55, so Z_{\text{eff}} = 16-10.55 = 5.45.

Adding one proton raises Z_{\text{eff}} by only 0.65 because the new electron screens 0.35 of it — this is why atoms shrink only gradually across a period.

3. IE₁ removes the 3s¹ electron from a neutral atom. IE₂ must break into the filled 2s²2p⁶ neon core of Na⁺, where the electron is in a lower shell, feels a much larger Z_{\text{eff}} and must be pulled away from a positive ion.

Hence the huge jump, and hence sodium's valency of 1.

4. Adding an electron to the very small fluorine atom forces it into a compact 2p subshell where inter-electronic repulsion is severe; chlorine's 3p subshell is larger, so more energy is released (F 328, Cl 349 kJ mol⁻¹).

Electron affinity is an energy (kJ mol⁻¹) belonging to an isolated gaseous atom; electronegativity is a dimensionless relative number describing a bonded atom's pull on a shared pair.

5. (i) C (77) < B (88) < Be (111) < Li (152) pm: across period 2, n is fixed but Z_{\text{eff}} rises, so the shell contracts. (ii) N³⁻ (171) > O²⁻ (140) > F⁻ (136) > Na⁺ (95) pm: isoelectronic, so radius falls as protons rise.

Group C — Long answer (8 marks each)

  1. (a) Classify the elements into s-, p-, d- and f-blocks, giving the general outer electronic configuration and one example of each. [4](b) Discuss the variation of atomic radius and first ionization energy along period 3, and explain the irregularities observed at aluminium and sulphur. [4]
  2. (a) Define ionization energy, electron affinity and electronegativity, and state how each varies across a period and down a group, with the reason. [5](b) An element X has atomic number 26. Write its ground-state electronic configuration and deduce its period, group and block. [3]
Answers to Group C

1.(b) Radius falls steadily 186 → 99 pm because Z_{\text{eff}} climbs from 2.20 to 6.10 while n = 3 throughout. IE₁ rises overall 496 → 1251 kJ mol⁻¹ but dips twice.

Al (578) < Mg (738): aluminium's electron comes from 3p, which is higher in energy and shielded by the filled 3s². S (1000) < P (1012): phosphorus is 3p³, half-filled and stable, whereas sulphur is 3p⁴ with one repelling pair.

2.(b) X is iron: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶ 4s². The outermost shell is n = 4, so the period is 4.

The last electron enters 3d, so it is a d-block element, and for groups 3–10 the group number = (number of d electrons) + (number of s electrons) = 6 + 2 = group 8. Common oxidation states +2 and +3.

Group D — Model answers for long questions (10 marks each, for deeper revision)

  1. State the modern periodic law. Discuss the periodic trends in atomic radius, ionisation energy, electron affinity and electronegativity across a period and down a group. [10]
  2. Describe the structure of the modern periodic table, its blocks, and the merits and demerits of Mendeleev's table compared with the modern table. [10]

Model answer D1: periodic trends (10 marks)

Introduction. The modern periodic law (Moseley, 1913) states that the physical and chemical properties of the elements are a periodic function of their atomic numbers. Properties repeat because the outer electron configurations repeat.

Two things control the trends: the effective nuclear charge Z_{eff} and the distance of the valence electrons from the nucleus.

1. Atomic radius.

  • Across a period (left to right): decreases. The nuclear charge increases while the electrons enter the same shell, so Z_{eff} rises and pulls the shell closer. Na (186 pm) to Cl (99 pm).
  • Down a group: increases. A new shell is added each time and the screening by inner electrons increases. Li (152 pm) to Cs (265 pm).

2. Ionisation energy (IE). The energy needed to remove the most loosely held electron from a gaseous atom: \text{M}(g) \rightarrow \text{M}^{+}(g) + e^{-}.

  • Across a period: increases, since the radius falls and Z_{eff} rises.
  • Down a group: decreases, as the outer electron is farther away and better shielded.
  • Exceptions: Be (900 kJ/mol) is higher than B (801) since 2s is more stable than 2p; N (1402) is higher than O (1314) since the half-filled 2p³ is stable.
  • IE₁ < IE₂ < IE₃, because it is harder to remove an electron from a positive ion. A big jump shows the removal of a core electron, which identifies the group of an element.
Element Na Mg Al Si P S Cl Ar
IE₁ (kJ/mol) 496 738 577 786 1012 1000 1251 1521

3. Electron affinity (EA). The energy released when a gaseous atom gains an electron.

  • Across a period: becomes more negative (more energy released). The halogens have the highest.
  • Down a group: decreases in general.
  • Exception: chlorine (-349 kJ/mol) has a higher electron affinity than fluorine (-328), because the small 2p subshell of F suffers strong electron-electron repulsion.
  • Noble gases and Be, N have values near zero or positive.

4. Electronegativity (EN). The ability of an atom in a bond to attract the shared electrons (Pauling scale, F = 4.0).

  • Increases across a period and decreases down a group. F (4.0) > O (3.5) > N, Cl (3.0) > C (2.5) > H (2.1).
  • Uses: predicting the polarity of a bond (the difference > 1.7 means mainly ionic) and the nature of oxides.
Property Across a period Down a group
Atomic radius Decreases Increases
Ionisation energy Increases Decreases
Electron affinity More negative Less negative
Electronegativity Increases Decreases
Metallic character Decreases Increases
Acidic nature of oxides Increases Decreases

Other trends. Ionic radius: a cation is smaller than its atom (Na⁺ 95 pm, Na 186 pm) and an anion is larger (Cl⁻ 181 pm, Cl 99 pm); in an isoelectronic series (N³⁻, O²⁻, F⁻, Na⁺, Mg²⁺, Al³⁺) the radius falls as the nuclear charge rises.

Conclusion. Periodic trends follow from the effective nuclear charge and the atomic size. They help to predict the reactivity, bond type and properties of the elements.

Model answer D2: structure of the modern periodic table and Mendeleev's table (10 marks)

Introduction. Early attempts to classify elements included Dobereiner's triads, Newlands' law of octaves and Lothar Meyer's curves. Mendeleev (1869) arranged the elements by increasing atomic mass, and Moseley (1913) showed that atomic number is the correct basis.

Structure of the modern table.

  • 18 vertical groups and 7 horizontal periods. Period 1 has 2 elements, periods 2 and 3 have 8 each, periods 4 and 5 have 18 each, period 6 has 32 and period 7 is incomplete.
  • Elements in a group have the same number of valence electrons and similar properties.
  • The period number is the number of the outermost shell.

Blocks.

Block Groups Last electron enters General configuration Nature
s 1, 2 s subshell ns^{1-2} Reactive metals (alkali, alkaline earth)
p 13-18 p subshell ns^{2}np^{1-6} Non-metals, metalloids, some metals, noble gases
d 3-12 d subshell (n-1)d^{1-10}ns^{0-2} Transition metals
f Lanthanides, actinides f subshell (n-2)f^{1-14} Inner transition metals

Merits of Mendeleev's table. (1) It was the first useful and systematic classification; (2) it predicted undiscovered elements, such as eka-aluminium (gallium), eka-silicon (germanium) and eka-boron (scandium), with their properties; (3) it corrected the atomic masses of some elements; (4) it left gaps for new elements.

Demerits of Mendeleev's table.

  1. Position of hydrogen was unclear.
  2. Anomalous pairs such as Ar (39.9) before K (39.1), and Te before I, break the order of atomic mass.
  3. Isotopes have different atomic masses but one position, and no place was given to them.
  4. Chemically dissimilar elements were put in the same group (Cu and Na).
  5. The position of lanthanides and actinides was not explained.

Advantages of the modern table. It is based on atomic number, so the anomalous pairs are resolved; it is related to electron configuration, which explains the periodicity; it separates the s, p, d and f blocks; it has a place for the isotopes, and a separate row for the lanthanides and actinides.

Feature Mendeleev's table Modern table
Basis Atomic mass Atomic number
Groups 8 (with subgroups) 18
Anomalies Ar-K, Te-I Resolved
Isotopes Problem No problem
Explanation Empirical Electron configuration

Conclusion. The modern periodic table links the position of an element to its electron configuration. It improved on Mendeleev's table, which was successful in predicting elements but had faults that were removed by the atomic number basis.

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